Nettet2. nov. 2015 · Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer Jim H Nov 2, 2015 ∫(cscx)2dx = − cotx + C Explanation: The derivative of cotx is csc2x, so the integral of csc2x is cotx + C If you really want the integral of the integral, then use: ∫[∫(cscx)2dx]dx = ∫[ − cotx + C]dx where C is an arbitrary constant Nettetit is simply a direct formula.. 1/sinx = cosecant (csc). hence n=cosecant. 11. d/dx (sinx + 3) someone solve this?? Answer: Cos x Step-by-step explanation: d/dx (sin x) + d/dx (3) Cos x + 0 d/dx (sin x +3)= cos x Step-by-step explanation: [tex] \frac {d ( \sin (x))} {dx} + \frac {d (3)} {dx} \\ \cos (x) + 0 \\ \cos (x) [/tex]
CSC-4351-Compiler-Construction/FindEscape.java at master - Github
http://csc.sadc.int/en/ ralph r willis
Manager Changement Social et Comportemental (CSC) - Mali
NettetLatest News and Events. The Twenty-sixth Southern Africa Regional Climate Outlook Forum (SARCOF-26) Climate Outlook Forum 2024 (SARCOF-25) Announcement: … Nettetמחשבונים לאלגברה, חשבון אינפיטיסימלי, גאומטריה, סטטיסטיקה, וכימיה כולל הדרך Nettet27. feb. 2024 · How can we find the integral of \csc^ {3}x csc3 x? Check out the solution below! \int \csc^ {3}x \, dx ∫ csc3 xdx. 1. Use Integration by Parts on \int \csc^ {3}x \, dx ∫ csc3xdx. Let u=\csc {x} u = cscx, dv=\csc^ {2}x dv = csc2 x, du=-\csc {x}\cot {x} \, dx du = −cscxcotxdx, v=-\cot {x} v = −cotx. 2. ralph r willis logan wv